Question

Tolong dong nomer 4-7

Answer 1

no 5)

f(x) = integral (x-3x^-2)dx =

f(x) = 1/2x² - 3/(-2+1)x^(-2+1) + C =

f(x) = 1/2x² + 3x^-1+ C

f(-1) = -2

berarti

1/2.(-1)² + 3(-1)^-1 + C = -2

1/2+ 3(-1) + C = -2

1/2 - 3 + C = -2

-5/2 + C = -2

C = -2 + 5/2

C = 1/2

f(x) = 1/2x² + 3x^-1 + 1/2

jadi :

f(2) = 1/2.2² + 3(2)^-1 + 1/2

f(2) = 2 + 3/2 + 1/2

f(2) = 8/2

f(2) = 4

no 6)

berarti

f(x) = integral (2x)^(1/3) dx =

misal u = 2x

du = 2 dx

dx = du/2

integral (2x) ^(1/3) dx =

integral u^(1/3).du/2 =

1/2 .integral u^(1/3) du =

1/2.1/(1/3+1)u^(1/3+1) du =

1/2.1/(4/3)u^(4/3) + C =

1/2.3/4 u^(4/3) + C =

3/8 u^(4/3) + C

3/8.(2x) ^(4/3) + C

f(4) = 16

3/8.(2.4)^(4/3) + C = 16

3/8.(2³)^(4/3) + C = 16

3/8.16 + C = 16

6 + C = 16

C = 10

konstantanya 10

dah ahh tangan gw pegel..