Question

Tolong dong caranya,jawaban saya sama kunci jawaban berbeda :((

Answer 1

Plog2 = 9 => p^(9) = 2 => p = 2^(1/9)
qlog4 = 8 => q^8 = 4 => q = (4)^(1/8) = (2)^2(1/8) = 2^(1/4)

s = p^3 = (2^(1/9))^3 = 2^(3/9) = 2^(1/3)
t = q^2 = (2^(1/4))^2 = 2^(2/4) = 2^(1/2)

tlogs = (2^1/2)log(2^(1/3)) = (1/3)/(1/2) . 2log2 = (1/3)(2/1) . 1 = 2/3