Tolong dong, bantuin nomor 8, 9, 10
Menggunakan Rumus ya, bukan pakai kalkulator. TerimaKasih..
Menggunakan Rumus ya, bukan pakai kalkulator. TerimaKasih..
Mujee
![\boxed{\boxed{\text{\bold{Nomor 9}}}}\\\\\displaystyle \sqrt[3]{\left(\frac{1}{243}\right)^{\displaystyle \frac{1}{6}x-\frac{1}{2}}} =\left(\frac{1}{243}\right)^0\\\\\frac{1}{6}x-\frac{1}{2}=0\\\\x=3](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Ctext%7B%5Cbold%7BNomor+9%7D%7D%7D%7D%5C%5C%5C%5C%5Cdisplaystyle++%5Csqrt%5B3%5D%7B%5Cleft%28%5Cfrac%7B1%7D%7B243%7D%5Cright%29%5E%7B%5Cdisplaystyle+%5Cfrac%7B1%7D%7B6%7Dx-%5Cfrac%7B1%7D%7B2%7D%7D%7D+%3D%5Cleft%28%5Cfrac%7B1%7D%7B243%7D%5Cright%29%5E0%5C%5C%5C%5C%5Cfrac%7B1%7D%7B6%7Dx-%5Cfrac%7B1%7D%7B2%7D%3D0%5C%5C%5C%5Cx%3D3 "\boxed{\boxed{\text{\bold{Nomor 9}}}}\\\\\displaystyle \sqrt[3]{\left(\frac{1}{243}\right)^{\displaystyle \frac{1}{6}x-\frac{1}{2}}} =\left(\frac{1}{243}\right)^0\\\\\frac{1}{6}x-\frac{1}{2}=0\\\\x=3")
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