Tolong.! Diketahui garis K : 2x + 3y = 2 Tentukan persamaan bayangan garis K oleh : a) Translasi (2 -3) b) Refleksi trhadap gari y = -4 c) Refleksi terhadap garis x + y = 0
savithree
A. translasi (2, -3) (x,y) ditranslasi (2,-3) -> ( x+2 , y-3) = (x',y') x' = x + 2 maka x = x' - 2 y' = y - 3 maka y = y' + 3 maka bayangan garis k = 2x + 3y = 2 adalah : k = 2 (x'-2) + 3 (y'+3) = 2 = 2x' - 4 + 3y' + 9 = 2 = 2x + 3y = -3
b. ( x, y) direfleksikan terhadap y = -4 (x,y) -> (2(-4)x , y) = (x' , y') (-8x , y) = (x',y') x' = -8x maka x = -x'/8 y' = y maka y = y' maka bayangan garis k = 2x + 3y = 2 adalah k= 2(-x/8) + 3y =2 = -x/4 + 3y = 2 dikali 4 biar gak pecahan -x + 12y = 8 atau 12y - x = 8
c. refleksi terhadap garis x + y = 0 sama aja y = -x x = -y matriksnya (0 -1 -1 0) jadi (x',y') = (0 -1 x (x -1 0) y) = (-y -x) maka x' = -y jadi y= -x' y'= -x jadi x = -y' maka bayangan garis k = 2x + 3y = 2 adalah 2(-y') + 3 (-x') = 2 -2y -3x =2 atau 3x + 2y = -2
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fadilahnurimani
Dik: K ≡ 2x + 3y = 2 Dit: bayangan garis K atau K'? Jwb: a)
x' = x + 2 ⇔ x = x' - 2 ..(1) y' = y - 3 ⇔ y = y' + 3 .. (2)
Subs. ke garis K K' ≡ 2(x' - 2) + 3(y' + 3) = 2 K' ≡ 2x' - 4 + 3y' + 9 = 2 K' ≡ 2x' + 3y' = -3 ⇒K' ≡ 2x + 3y = -3
b)
x' = x ⇔ x = x' y' = - y - 8 ⇔ y = -y' - 8
Subs. ke garis K K' ≡ 2(x') + 3(-y' - 8) = 2 K' ≡ 2x' - 3y' - 24 = 2 K' ≡ 2x' - 3y' = 26 ⇒K' ≡ 2x - 3y = 26
c) Karena x + y = 0 ⇔ y = - x Maka:
x' = -y ⇔ y = - x' y' = - x ⇔ x = - y' Subs. ke garis K K' ≡ 2(-y') + 3(-x') = 2 K' ≡ - 3x' - 2y' = 2 K' ≡ - 3x - 2y = 2
(x,y) ditranslasi (2,-3) -> ( x+2 , y-3) = (x',y')
x' = x + 2 maka x = x' - 2
y' = y - 3 maka y = y' + 3
maka bayangan garis k = 2x + 3y = 2 adalah :
k = 2 (x'-2) + 3 (y'+3) = 2
= 2x' - 4 + 3y' + 9 = 2
= 2x + 3y = -3
b. ( x, y) direfleksikan terhadap y = -4
(x,y) -> (2(-4)x , y) = (x' , y')
(-8x , y) = (x',y')
x' = -8x maka x = -x'/8
y' = y maka y = y'
maka bayangan garis k = 2x + 3y = 2 adalah
k= 2(-x/8) + 3y =2
= -x/4 + 3y = 2
dikali 4 biar gak pecahan
-x + 12y = 8 atau 12y - x = 8
c. refleksi terhadap garis x + y = 0 sama aja y = -x
x = -y matriksnya (0 -1
-1 0)
jadi (x',y') = (0 -1 x (x
-1 0) y)
= (-y
-x)
maka x' = -y jadi y= -x'
y'= -x jadi x = -y'
maka bayangan garis k = 2x + 3y = 2 adalah
2(-y') + 3 (-x') = 2
-2y -3x =2 atau 3x + 2y = -2
Dit: bayangan garis K atau K'?
Jwb:
a)
x' = x + 2
⇔ x = x' - 2 ..(1)
y' = y - 3
⇔ y = y' + 3 .. (2)
Subs. ke garis K
K' ≡ 2(x' - 2) + 3(y' + 3) = 2
K' ≡ 2x' - 4 + 3y' + 9 = 2
K' ≡ 2x' + 3y' = -3
⇒K' ≡ 2x + 3y = -3
b)
x' = x
⇔ x = x'
y' = - y - 8
⇔ y = -y' - 8
Subs. ke garis K
K' ≡ 2(x') + 3(-y' - 8) = 2
K' ≡ 2x' - 3y' - 24 = 2
K' ≡ 2x' - 3y' = 26
⇒K' ≡ 2x - 3y = 26
c)
Karena x + y = 0 ⇔ y = - x
Maka:
x' = -y
⇔ y = - x'
y' = - x
⇔ x = - y'
Subs. ke garis K
K' ≡ 2(-y') + 3(-x') = 2
K' ≡ - 3x' - 2y' = 2
K' ≡ - 3x - 2y = 2
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