Question

Tolong dikerjakan dengan benar kalau ngasal saya laporkan

Answer 1

Penjelasan dengan langkah-langkah:

1.

Segitiga istimewa 30 60 90

KL : LM : KM

√3 : 2 : 1

maka

KM : KL = 1 : √3

KM : 12√3 = 1 : √3

KM = 12√3 / √3

KM = 12 cm

LM : KL = 2 : √3

LM = 12√3 x 2 /√3

LM = 24 cm

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2.

Segitiga istimewa 30 60 90

QR : PR : PQ

√3 : 2 : 1

PQ : PR = 1 : 2

PQ = 100 x 1 : 2

PQ = 50 cm

QR : PR = √3 : 2

QR = 100 x √3/2

QR = 50√3 cm

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3.

Segitiga istimewa 45 45 90

AB : BC : AC

1 : 1 : √2

AC : AB = √2 : 1

AC = 10√5 x √2 : 1

AC = 10√10 cm

BC = AC

BC = 10√5 cm

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4.

Aturan siinus

AC/Sin B = AB/Sin C = BC/Sin A

BC/Sin 45° = AC/Sin 30°

BC/½√2 = 8/½

BC / ½√2 = 16

BC = 16 x ½√2

BC = 8√2 cm

BC = 11,3 cm

AB/Sin 105°= AC/Sin 30°

AB/¼(√6 + √2) = 8/½

AB/¼(√6 + √2) = 16

AB = 4√6 + 4√2 cm

AB = 15,4 cm

Keliling

= 8 + 11,3 + 15,4

= 34,8 cm

Luas segitiga

s = ½ k

s = 17,4

L = √s(s-a)(s-b)(s-c)

L = √17,4(17,4-8)(17,4-11,3)(17,4-15,4)

L = √17,4(9,4)(6,1)(2)

L = √1995,432

L = 44,6 cm²

Maaf kalau ada yang salah bisa saya koreksi , soalnya ini pake sinus

Answer 2

1) KM = 12√3/√3

= 12/√3√3

= 12 CM

LM = 12√3(2/√3)

= 12(2(√3/√3)

= 12(2)

= 24 CM

2) PQ = 100(1)/2

= 100/2

= 50/1

= 50 CM

QR = 100(√3/2)

= 100/2(√3)

= 50/1(√3)

= 50√3 CM

3) AC = 10√5(√2)

= 10(√5(√2)

= 10(√(5(2)

= 10√10 CM

BC = 10√10 CM