Misalkan : banyaknya Ayam = x dan banyaknya Kambing = y maka banyak kaki ayam = 2x dan banyak kaki kambing = 4y
Diketahui :
y = 3+x
4y= 4(3+2x)
2x+4y=102
Ditanyakan : A. 2x = ? B. 4y = ? C. x = ?
Penyelesaian :
C.) 2x + 4y = 102
2x + 4(3+2x) = 102
____________________/2
x + 2(3+2x) = 51
x + 6 + 4x = 51
____________________-6
5x = 51 - 6
x = 45/5
x = 9
A.) 2x = 2(9) = 18
B.) 4y = 4(3+2x) = 4(3+18) = 4(21) = 84
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Misalkan : banyaknya Ayam = x dan banyaknya Kambing = y maka banyak kaki ayam = 2x dan banyak kaki kambing = 4y
Diketahui :
y = 3+x
4y= 4(3+2x)
2x+4y=102
Ditanyakan : A. 2x = ? B. 4y = ? C. x = ?
Penyelesaian :
C.) 2x + 4y = 102
2x + 4(3+2x) = 102
____________________/2
x + 2(3+2x) = 51
x + 6 + 4x = 51
____________________-6
5x = 51 - 6
x = 45/5
x = 9
A.) 2x = 2(9) = 18
B.) 4y = 4(3+2x) = 4(3+18) = 4(21) = 84
Ayam = x
Kambing = 3 + x
C. 2x + 4( 3 + x ) = 102
2x + 12 + 4x = 102
6x + 12 = 102
6x = 102 - 12
6x = 90
x = 90/6
x = 15
A. 2x
= 2( 15 )
= 30
B. 4( 3 + x )
= 4( 3 + 15 )
= 4( 18 )
= 72