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hrg sepatu = x
harga sendal y
maka :
2x + 3y = 540.000 ......dikali 3
3x + 4y = 780.000 ......dikali2
diperoleh :
6x + 9y = 1.620.000
6x + 8y = 1.560.000 -
y = 60.000
subtitusi nilai y
2x + 3y = 540.000
2x + 3 (60.000) = 540.000
2x = 540.000 - 180.000
x = 360.000 / 2
x = 180.000
jadi sepasang sepatu + 2 sendal = 180.000 + 120.000 =Rp 300.000
3p.spt+4p.sndl= 780.000 |x 2
=6p.spt+9p.sndl= 1.620.000
6p.spt+8p.sndl= 1.560.000
--------------------------------------------- _
1p.sndl= 60.000
=> 2p.sndl = 120.000
=>2p.spt+3(60.000)p.sndl = 540.000
2p.spt+180.000. = 540.000
2p.spt. = 540.000 - 180.000
2p.spt. =360.000
p.spt. = 360.000: 2
=180.000