Question

Tolong dijawab ya, poinnya besar
lagi butuh banget nih :))​

Answer 1

Penjelasan dengan langkah-langkah:

PythaGoras

a) panjang AC

AC² = 50²-14²

AC² = 2500-196

AC² = 2304

AC = √2304

AC = 48 cm

b) Luas segitiga

= ½ × 48 × 14

= 48 × 7

= 336 cm²

c) Luas layang layang

= 2 × 336

= 672 cm²

d) Panjang tali busur AB

672 = ½ ( OC × AB)

672 = ½ (50 × AB)

AB = 672/25

AB = 26,88 cm

Answer 2

A) P.AC :

= √50² - 14²

= √(50(50) - (14(14)

= √2.500 - 196

= √2.304

= √48²

= 48 CM

B) LP∆ :

= 1/2(48(14)

= 48/2(14)

= 24(14)

= 336 CM²

C) LP. LAYANG-LAYANG :

= 2LP∆

= 2(336)

= 672 CM²

D) 672 = 1/2(50(AB)

672 = 50/2(AB)

672 = 25AB

25AB = 672

AB = 672/25

AB = 26,88 CM

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