b. ∠H = ∠D = 60° c. ∠G = 180 - 60 = 120° d. EH = 3/10 x AD = 3/10 x 140 = 42 cm e. CD cos 60 = (AD-BC) / CD 1/2 = (140-80) / CD 1/2 = 60 / CD CD = 60 x 2 CD = 120 cm
f. AB = 20x sin 60 = AB / CD √3/2 = 20x / 120 40x = 120√3 x = 3√3
g. FG = 3/10 x BC = 3/10 x 80 = 24 cm h. HG = 3/10 x CD = 3/10 x 120 = 36 cm
Verified answer
3a.faktor skala = EF / AB = 6 / 20 = 3 / 10
b. ∠H = ∠D = 60°
c. ∠G = 180 - 60 = 120°
d. EH = 3/10 x AD = 3/10 x 140 = 42 cm
e. CD
cos 60 = (AD-BC) / CD
1/2 = (140-80) / CD
1/2 = 60 / CD
CD = 60 x 2
CD = 120 cm
f. AB = 20x
sin 60 = AB / CD
√3/2 = 20x / 120
40x = 120√3
x = 3√3
g. FG = 3/10 x BC = 3/10 x 80 = 24 cm
h. HG = 3/10 x CD = 3/10 x 120 = 36 cm