Question

Tolong dijawab ya nomer 38 & 39

Answer 1

Nomor 38
n(S) = 6 x 6 = 36
n(A) = 2    ---->   { 5, 6 }

Maka,
p(A) = n(A) / n(S)
        = 2/36
        = 1/6

(JAWABAN D)


Nomor 39
n(S) = 8    ---->    {AAA, AAG, AGA, AGG, GAA, GAG, GGA, GGG}.
n(A) = 3    ---->    {AAG, AGA, GAA}

p(A) = n(A) / n(S)
        = 3/8

Fh(A) = n x P(A)
          = 72 x 3/8
          = 27 kali

(JAWABAN B)

Answer 2

38) n(S) = 6x6 = 36
titk sampel = 30
(1,4)(1,5)(1,6)(2,3)(2,4)(2,5)(2,6)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
peluan mata dadu lbh dr 4 = 30/66 =5/6
39) AAA,AGG,AAG,AGA,GAA,GGG,GAG,GGA
 peluang muncul 1 gambar = AGA, GAA, AGG
F(H) =3/8 x 72
= 27