DiahYusi
13. Luas Permukaan keruscut = πrs + πr² (B)
14. - luas alas = πr² 314 = 3,14 x r² r² = 314/3,14 r² = 100 r = √100 r = 10 cm - tinggi kerucut² = garis pelukis² - r² t² = 26² - 10² t² = 676 - 100 t² = 576 t = √576 t = 24 cm - volume = 1/3 x πr²t = 1/3 x 3,14 x 10 x 10 x 24 = 2512 cm³ (C)
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ekamiaww
13) Luas kerucut = Luas selimut kerucut + luas alas = πrs + πr²
14) Luas alas kerucut = πr² 314 = 3,14 x r² r² = 100 r = 10 cm s = 26 cm maka t = 24 cm (bil triple Pythagoras) volume kerucut = 1/3.πr²t = 1/3 x 3,14 x 10 x 10 x 24 = 2512 cm³
14. - luas alas = πr²
314 = 3,14 x r²
r² = 314/3,14
r² = 100
r = √100
r = 10 cm
- tinggi kerucut² = garis pelukis² - r²
t² = 26² - 10²
t² = 676 - 100
t² = 576
t = √576
t = 24 cm
- volume = 1/3 x πr²t
= 1/3 x 3,14 x 10 x 10 x 24
= 2512 cm³ (C)
= πrs + πr²
14) Luas alas kerucut = πr²
314 = 3,14 x r²
r² = 100
r = 10 cm
s = 26 cm
maka t = 24 cm (bil triple Pythagoras)
volume kerucut = 1/3.πr²t
= 1/3 x 3,14 x 10 x 10 x 24
= 2512 cm³