5dregensleyerjawabn soal A tinggi segitiga t² = ( 1/2x 12√2)² + 8² t² = (6√2)² + 64 t² = 36√4 + 64 t² = 72+64 t = √72+64 t = √136 t = 2 √34 luas = 1/2 x a x t = 1/2 x 12√2 x 2√34 = 6√2 x 2√34 = 12√68 = 24√17 cm² jawaban soal B VOLUM =1/3 x s x s x t = 1/3 x 12√2 x 12√2 x 8 = 4√2 x 12√2 x 8 = 48√4 x 8 = 96 x 8 = 768 cm³
tinggi segitiga
t² = ( 1/2x 12√2)² + 8²
t² = (6√2)² + 64
t² = 36√4 + 64
t² = 72+64
t = √72+64
t = √136
t = 2 √34
luas = 1/2 x a x t
= 1/2 x 12√2 x 2√34
= 6√2 x 2√34
= 12√68
= 24√17 cm²
jawaban soal B
VOLUM =1/3 x s x s x t
= 1/3 x 12√2 x 12√2 x 8
= 4√2 x 12√2 x 8
= 48√4 x 8
= 96 x 8
= 768 cm³