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3'log 105 = 3'log ( 3 x 5 x 7)
3'log 3 + 3'log 5 + 3'log 7 = 1 + 1,465 + 1,771 = 4.236
4) log 9 - log 4 = log (9/4) = log (3/2)^2
= 2 ( log 3 - log 2)
= 2q - 2p
5)
3'log 4 = p --> 4'log 3 = 1/p
5'log 4 = q --> 4'log 5 = 1/q
4'log 15 = 4'log 5 + 4'log 3 = 1/p + 1/q = (p+q)/(pq)