Jawab:
Penjelasan dengan langkah-langkah:
sin 120 = sin (180 - 60)
= sin 60
= ½ V3
V = akar
cos 210 = cos (180 + 30)
= - cos 30
= - ½ V3
cos 330 = cos (360 - 30)
= cos 30
tan 60 = V3
(sin 120 - cos 210)/(cos 330 - tan 60) =
(½V3 - (-½V3))/(½V3 - V3) = (½V3 + ½V3)/(½V3 - V3)
= V3 / (-½V3)
= - 2.
Materi : Trigonometri
( sin 120 - cos 210 )/( cos 330 - tan 60 )
= ( √3/2 - [ - √3/2 ] )/( √3/2 - √3/2 ÷ ½ )
= ( √3/2 + √3/2 )/( √3/2 - √3 )
= √3/( - √3/2 )
= √3 × ( - 2/√3 )
= -2
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Jawab:
Penjelasan dengan langkah-langkah:
sin 120 = sin (180 - 60)
= sin 60
= ½ V3
V = akar
cos 210 = cos (180 + 30)
= - cos 30
= - ½ V3
cos 330 = cos (360 - 30)
= cos 30
= ½ V3
tan 60 = V3
(sin 120 - cos 210)/(cos 330 - tan 60) =
(½V3 - (-½V3))/(½V3 - V3) = (½V3 + ½V3)/(½V3 - V3)
= V3 / (-½V3)
= - 2.
Materi : Trigonometri
( sin 120 - cos 210 )/( cos 330 - tan 60 )
= ( √3/2 - [ - √3/2 ] )/( √3/2 - √3/2 ÷ ½ )
= ( √3/2 + √3/2 )/( √3/2 - √3 )
= √3/( - √3/2 )
= √3 × ( - 2/√3 )
= -2
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]