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5×=2+3
×=5/5=1
2) diketahui: titik (9,7) dan (11,-1)
×1=9 ,×2=11
y1=7 ,y2=-1
rumus gradien
m =y2-y1 / x2-×1
m=(-1-7) / (11-9)
m= -8 /2 =-4
3) (2×-5)(×+1) / (2×+5)(2×-5)
(×+1) /(2×+5)
4) dik: rumus pers. garis:
y-y1/y2-y1 = ×-×1/×2-x1
(y-7)/ (-1-7) = ×-(-4) / 10-(-4)
(y-7)/ -8 = (×+4) / 14 (dikali silangl
14y-98 = -8×-32
14y+8×-98+32=0
14y+8×-66 =0 (dibagi 2)
7y+4×-33 =0 atau 7y=-4×+33
5) 2×-5=3
2×=3+5
2×=8
×=8/2=4
jadi x+-6
4+(-6)=-2