Question

Tolong dijawab pakai CARA !!!

Answer 1

Nomer 9

Deret geometri
lintasan turun
6, 2, 2/3, ....
a = 6
r = 1/3
lintasan naik
2, 2/3, 2/9 ....
a = 2
r = 1/3

S = a / (1-r)
lintasan turun
S = 6 / (1-1/3) = 6/(2/3) = 6x(3/2) = 9 m
lintasan naik
S = 2 (1-1/3) = 2/(2/3) = 2x(3/2) = 3

panjang seluruh lintasan = 9+3 = 12
(jawaban D)



nomer 10

suku pertama = 5
5, p, q, r, s, t
rasio = R

suku ganjil
5, q, s, ...
Rasio = R2
S = a / (1-r) = 5 / 1-R2 = 9
9 - 9R2 = 5
9R2 = 9 - 5 = 4
R2 = 4/9
R = √R2 = √4/9 = 2/3

Panjang lintasan
S = a / (1-r) = 5 / (1-(2/3)) = 5 / (1/3)
= 5.3 = 15
(jawaban B)