menghitung orde NO kita gunakan no 3 dan 2 V₃/V₂ = (k[NO]ᵃ[O₂]ᵇ)/(k[NO]ᵃ[O₂]ᵇ) 0.08/0.02 = (k(0.2)ᵃ(0.2)ᵇ)/(k(0.1)ᵃ(0.2)ᵇ) 4 = (0.2)ᵃ/(0.1)ᵃ 4 = 2ᵃ a = 2 menghitung orde O₂ kita gunakan no 2 dan 1 V₂/V₁ = (k[NO]ᵃ[O₂]ᵇ)/(k[NO]ᵃ[O₂]ᵇ) 0.02/0.01 = (k(0.1)ᵃ(0.2)ᵇ)/(k(0.1)ᵃ(0.1)ᵇ) 2 = (0.2)ᵇ/(0.1)ᵇ 2 = 2ᵇ b = 1 rumus laju reaksi v = k[NO]²[O₂]¹ menghitung tetapan kita ambil contoh dari no 1 v = k[NO]²[O₂]¹ k= v/([NO]²[O₂]¹) = 0.01 / ((0.1)²(0.1)¹) = 10 M⁻²S⁻¹
menghitung orde NO kita gunakan no 3 dan 2
V₃/V₂ = (k[NO]ᵃ[O₂]ᵇ)/(k[NO]ᵃ[O₂]ᵇ)
0.08/0.02 = (k(0.2)ᵃ(0.2)ᵇ)/(k(0.1)ᵃ(0.2)ᵇ)
4 = (0.2)ᵃ/(0.1)ᵃ
4 = 2ᵃ
a = 2
menghitung orde O₂ kita gunakan no 2 dan 1
V₂/V₁ = (k[NO]ᵃ[O₂]ᵇ)/(k[NO]ᵃ[O₂]ᵇ)
0.02/0.01 = (k(0.1)ᵃ(0.2)ᵇ)/(k(0.1)ᵃ(0.1)ᵇ)
2 = (0.2)ᵇ/(0.1)ᵇ
2 = 2ᵇ
b = 1
rumus laju reaksi
v = k[NO]²[O₂]¹
menghitung tetapan
kita ambil contoh dari no 1
v = k[NO]²[O₂]¹
k= v/([NO]²[O₂]¹)
= 0.01 / ((0.1)²(0.1)¹)
= 10 M⁻²S⁻¹