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kambing=y
1x=10y
2x+8y=11,9
2(10y)+8=11,9
2oy+8=11,9
20y=11,9-8=3,9
y=3,9/20
y=39/200
y=0,195
1x=10y
1x=10(0,195)
1x=1,95
x=1,95/1
x=1,95
jadi,harga satu ekor sapi adalah 1,95 juta
dimisalkan kambing = y
x=10y
2x+8y=11.900.000
x-nya dimasukkan
2(10y)+8y=11.900.000
20+2y+8y=11.900.000
20+10y=11.900.000
10y=11.900.000
y=1.190.000
2x+8y=11.900.000
y-nya dimasukkan
2x+8(1190000)=11.900.000
2x+9520000=11.900.000
2x=11.900.000-9.520.000
2x=2380000
x=1.190.000
kalau dihitung harga 1 sapi rp 1.190.000,00