Question

Tolong dijawab dg caranya

Answer 1

Verified answer

Kelas 9 Matematika
Bab Akar dan Pangkat

^ = pangkat

Nomor 1

((6a² . b^-3)/(15a^-1 b^-5))^-2
= ((15a^-1 b^-5)/(6a² . b^-3))²
= (5 . a^(-1 - 2) . b^(-5 + 3)/2)²
= ((5 . a^-3 . b^-2)/2)²
= (25/4) a^-6 . b^-4

Jika

((5 a^-3 . b^-2)/2)^3
= (125/8) . a^-9 . b^-6

Nomor 2

√(54) + 2√(24) - √(150) + 3 √(96)
= √9 . √6 + 2 . √4 . √6 - √25 . √6 + 3 . √16 . √6
= 3√6 + 2 . 2√6 - 5√6 + 3 . 4√6
= 3√6 + 4√6 - 5√6 + 12√6
= 14√6