Jawab:
Turunan
Penjelasan dengan langkah-langkah:
f(x) = 1/3 x³ - 2x² + 4x + 3
f'(x) = x² - 4x + 4
.
f '(x) = 0
x² - 4x + 4= 0
x = 2
garis bilangan ....++......(2).. +++
i) fungsi naik x< 2 atau x > 2
ii) fungsi turun, (tidak pernah turun)
iii) nilai titi stationer f(2)= 1/3 (2³) - 2 (2²) + 4(2) + 3
f(2) = 8/3 - 8 + 8 + 3
f(2) = 8/3 + 3 = 17/3
Iv) titik stationer (x, y) = (2 , 17/3)
v) Jenis , titik belok
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Verified answer
Jawab:
Turunan
Penjelasan dengan langkah-langkah:
f(x) = 1/3 x³ - 2x² + 4x + 3
f'(x) = x² - 4x + 4
.
f '(x) = 0
x² - 4x + 4= 0
x = 2
garis bilangan ....++......(2).. +++
i) fungsi naik x< 2 atau x > 2
ii) fungsi turun, (tidak pernah turun)
iii) nilai titi stationer f(2)= 1/3 (2³) - 2 (2²) + 4(2) + 3
f(2) = 8/3 - 8 + 8 + 3
f(2) = 8/3 + 3 = 17/3
Iv) titik stationer (x, y) = (2 , 17/3)
v) Jenis , titik belok