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CB² = AB² + AC²
CB² = 3² + 4²
CB² = 9 + 16
CB² = 25
CB = √25
CB = 5 cm
ΔPQR :
PQ² = QR² - PR²
PQ² = 20² - 16²
PQ² = 400 - 256
PQ² = 144
PQ = √144
PQ = 12
PEMBUKTIAN
AB : PQ = 3 : 12 = 1 : 4
AC : PR = 4 : 16 = 1 : 4
CB : QR = 5 : 20 = 1 : 4
→JADI ΔABC dan ΔPQR sebangun, karena sisi-sisi yang bersesuaian sebanding,
GOOD LUCK