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< RPQ = 70 = < APB
< PQR = 50 = < ABP (karena garis RQ dan garis AB sejajar)
maka,
< BAP = 180 - (< APB + < ABP)
= 180 - ( 70 + 50 )
= 180 - 120
= 60
< RAB = 180 - < BAP
= 180 - 60
< RAB = 120 (B)
sdut q =50 maka, sudut r = 180-(70+50) (mengapa dkurang 180 karena jmlah sudut segitiga 180)
jadi sudut r =60
sdut b=sdut q maka sdut b juga 50
jadi sudut bar 180-60= 120 (dkurangi 180 karena sdut pab+sdut rab= 180)