Question

Tolong dibantu ya temen temen..

Answer 1

Dik : lambda: 6000A = 6x10^-7
R: 5m
I: 5 mW/m^2
Dit : N?
Jawab :
E = Nhf
Pt = Nh(c/lambda)
Ix4phixR^2xt = Nh(c/lambda)
N = (5x10^-3 x 4phi x 25 x 1 x 6x10^-7)/(6,6x10^-34 x 3x10^8)
N = (5phi x 10^-8)/(3,3x10^-26)
N = 4,76 x 10^18