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x²-8x+16 > 4x-16+12
x²-12x+20>0
(x-2)(x-10)>0
titik kritis= x=2 dan x=10
sihingga Hp= {x|x<2 dan x>10, x∈r}
2. (x-1)²+2(x-1)<15
x²-2x+1+(2x-2)-15<0
x²-16<0
x²<16
x<4
3. √4x-3<x (semua nya di kuadratkan)
4x-3<x²
x²-4x+3<0
(x-1)(x-3)
titik kritis = x=1 dan x=3
sehingga Hp : {x|1<x<3,x∈r}