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t = terlarut (glukosa)
mp = 100 - 36 = 64 gram
P° = 20 mmHg
Kb air = 0,52 °C/molal
Kf air = 1,86 °◦C/molal
Mr glukosa = 180
Ditanya: P? Tb? Tf?
**Rumus bisa dicari di buku kimia ya :)
nt = mt/Mr = 36/180 = 0,2 mol
np = mp/Mr = 64/18 = 3,55 mol
Xp = np/ (np+nt) = 3,55/ (3,55 + 0,2) = 3,55/3,75 = 0,947
P = Xpelarut . P° = 0,947 . 20 = 18,94 mmHg
m = nt . 1000/p = 0,2 . 1000/64 = 3,125 molal
∆Tb = m . Kb = 3,125 . 0,52 = 1,625 °C
Tb = ∆Tb + Tb° = 100 + 1,625 = 101,625 °C
∆TF = m . Kf = 3,125 . 1,86 = 5,8125 °C
Tf = Tf° - ∆Tf = 0 – 5,8125 = -5,8125 °C