u = x+3 => √(x+3) = √(u)
x = u-3
x³ = (u-3)³
batas berubah :
x = 6, => u = 6+3 = 9
x = 1 => u = 1+3 = 4
Jawaban :
ba
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u = x+3 => √(x+3) = √(u)
x = u-3
x³ = (u-3)³
batas berubah :
x = 6, => u = 6+3 = 9
x = 1 => u = 1+3 = 4
Jawaban :
ba
Jika disubstitusi u = x + 3, maka batas integral juga ikut berubah jika dalam u, maka :
x = u-3
Jadi :
Jawaban : B.
Semoga membantu.