Jawaban:
15Ω
Penjelasan:
i1 = 0,3 A
R1 = 20 Ω
i2 = x
R2 = 60 Ω
V LED = 3V
V1 = i1 × R1
= 0,3 × 20
= 6V
tegangan dalam pararel V1 = V2
i2 = V2 ÷ R2
= 6 ÷ 60
= 0,1 A
rumus mengetahui tegangan tiap hambatan
[tex]volt \: led \: = \: \frac{r \: led}{r \: led + r \: pararel} \times volt \: catu \: daya[/tex]
ketika diseri hambatan nya jadi 15 Ω
sehingga
[tex]3 \: volt \: = \frac{x}{x + 15} \times 6[/tex]
x= 15 Ω
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Jawaban:
15Ω
Penjelasan:
i1 = 0,3 A
R1 = 20 Ω
i2 = x
R2 = 60 Ω
V LED = 3V
V1 = i1 × R1
= 0,3 × 20
= 6V
tegangan dalam pararel V1 = V2
i2 = V2 ÷ R2
= 6 ÷ 60
= 0,1 A
rumus mengetahui tegangan tiap hambatan
[tex]volt \: led \: = \: \frac{r \: led}{r \: led + r \: pararel} \times volt \: catu \: daya[/tex]
ketika diseri hambatan nya jadi 15 Ω
sehingga
[tex]3 \: volt \: = \frac{x}{x + 15} \times 6[/tex]
x= 15 Ω