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m = 2.000 kg
h = 5 m
S = 10 m
s = 8 m
Penyelesaian :
a. KM pada katrol = 1 (krn hanya 1 katrol yaitu jns katrol tetap)
KM pd bidang miring = s/h
= 10/5
= 2
b. F u/ menaikkan balok :
F = h/S x W
F = 5/10 x ( 2000x10)
= 1/2 x 20.000
= 10.000 N
Gaya F kemudian dibagi ke dua buah tali, satu dipegang anak dan satu lagi terikat pada tonggak, sehingga :
Fanak = F : 2
= 10.000 : 2
= 5.000 N
KM gabungan = W/Fanak
= 20000/5.000
= 4
c. W = F x s
= 10.000 x 8
= 80.000 J