Tolong dibantu no 11dan 20 dengan jawaban yang benaar dan tepat jangan asal!
Syubbana
No 11) phi x r x (r+s) = luas permukaan 3,14 x 9 x (9+s) = 678,24 254,34 + 28,26s = 678,24 28,26s = 678,24-254,34 28,26s = 423,9 s = 423,9/28,26 s = 15
t = V(15^2 - 9^2) t = V(225 - 81) t = V144 t = 12
volume = 1/3 x phi x r^2 x t = 1/3 x 3,14 x 9^2 x 12 = 1017,36
jawaban C
no 20 )
t = V(25^2 - 7^2) = V(625 - 49) = 24
volume = volum belahan bola + volum kerucut = 1/2 x 4/3 x 22/7 x 7^3 + 1/3 x 22/7 x 7^2 x 24 = 718,67 + 1232 = 1950,67
berat gandul = 1950,67 x 6 = 11704,02 = 11,70402 kg
phi x r x (r+s) = luas permukaan
3,14 x 9 x (9+s) = 678,24
254,34 + 28,26s = 678,24
28,26s = 678,24-254,34
28,26s = 423,9
s = 423,9/28,26
s = 15
t = V(15^2 - 9^2)
t = V(225 - 81)
t = V144
t = 12
volume = 1/3 x phi x r^2 x t
= 1/3 x 3,14 x 9^2 x 12
= 1017,36
jawaban C
no 20 )
t = V(25^2 - 7^2)
= V(625 - 49)
= 24
volume = volum belahan bola + volum kerucut
= 1/2 x 4/3 x 22/7 x 7^3 + 1/3 x 22/7 x 7^2 x 24
= 718,67 + 1232
= 1950,67
berat gandul = 1950,67 x 6
= 11704,02
= 11,70402 kg
jawaban B