[tex]28).diameter \\ \sqrt{Luas \div ( \frac{\pi}{4} )} \\ \sqrt{314 \div \frac{3,14}{4} } \\ \sqrt{314 \times \frac{4}{3,14} } \\ \sqrt{400} \\ 20 \: m \\ \\ lebar \\ \sqrt{ {d}^{2} - {p}^{2} } \\ \sqrt{ {20}^{2} - {16}^{2} } \\ \sqrt{400 - 256} \\ \sqrt{144} \\ 12 \: m \\ \\ Luas \: kolam \\ panjang \times lebar \\ 16 \: m \times 12 \: m \\ 192 \: {m}^{2} \\ \\ \\ 30).tinggi \: kerucut \\ Volume \div ( \frac{1}{3} \times \pi \times r \times r) \\ 9.240 \div ( \frac{1}{3} \times \frac{22}{7} \times 21 \times 21) \\ 9.240 \div 462 \\ 20 \: cm[/tex]
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[tex]28).diameter \\ \sqrt{Luas \div ( \frac{\pi}{4} )} \\ \sqrt{314 \div \frac{3,14}{4} } \\ \sqrt{314 \times \frac{4}{3,14} } \\ \sqrt{400} \\ 20 \: m \\ \\ lebar \\ \sqrt{ {d}^{2} - {p}^{2} } \\ \sqrt{ {20}^{2} - {16}^{2} } \\ \sqrt{400 - 256} \\ \sqrt{144} \\ 12 \: m \\ \\ Luas \: kolam \\ panjang \times lebar \\ 16 \: m \times 12 \: m \\ 192 \: {m}^{2} \\ \\ \\ 30).tinggi \: kerucut \\ Volume \div ( \frac{1}{3} \times \pi \times r \times r) \\ 9.240 \div ( \frac{1}{3} \times \frac{22}{7} \times 21 \times 21) \\ 9.240 \div 462 \\ 20 \: cm[/tex]