Jawaban:
1.diketahui :
a = 6 cm
t = 8 cm
t priama = 20 cm
di tanya :
v?
jawab :
v = la × t prisma
v = ½ × a × t prisma
v = ½ × 6 × 8 × 20
v = 3 × 8 × 20
v = 450 cm²
2. v = luas × tinggi
v = 16 × 24 ×25
v = 348 × 25
v= 9.600 cm ^ 3
3. la = 240 cm²
v = 1/ 3 la × t
= 1/ 3 × 240 cm² × 30 cm
= 240 cm² × 10 cm
= 2400 cm²
4.luas alas
la = ½ × 6 × 8
= 6 × 4
= 24 cm²
volume = la × t
432. = 24 × t
432/24 = t
18. = t
= 18 cm
Penjelasan dengan langkah-langkah:
• Diketahui
Tinggi prisma = 20 cm
Alas segitiga = 6 cm
Tinggi segitiga = 8 cm
• Ditanyakan
Volume?
• Jawab
V = luas alas × t
= (½ × a × t) × t
= (½ × 6 × 8) × 20
= (3 × 8) × 20
= 24 × 20 =
Panjang diagonal 1 = 16 cm
Panjang diagonal 2 = 24 cm
Tinggi prisma = 25 cm
= (½ × × × t
= (½ × 16 × 24) × 25
= (8 × 24) × 25
= 192 × 25 =
Luas alas = 240 cm²
Tinggi limas = 30 cm
V = ⅓ × luas alas × t
= ⅓ × 240 × 30
= 80 × 30 =
Volume = 432 cm³
Tinggi Prisma?
T =
=
Alas segitiga = 30 cm
Tinggi segitiga = 40 cm
V = luas alas × tinggi
= (½ × 30 × 40) × 20
= (15 × 40) × 20
= 600 × 20 = 12.000 cm³
Panjang = 80 cm
Lebar = 40 cm
Tinggi = 50 cm
V = p × l × t
= 80 × 40 × 50
= 3.200 × 50 = 160.000 cm³
Tinggi Prisma = 18 dm
Alas segitiga = 6 dm
Tinggi segitiga = 8 dm
= (½ × 6 × 8) × 18
= (3 × 8) × 18
= 24 × 18 = 432 dm³
Mapel: Matematika
Kelas: 8
Bab: Bab 8 Bangun Ruang
Kode kategorisasi: 8.2.8
Kata kunci: Volume, Bangun Ruang
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Jawaban:
1.diketahui :
a = 6 cm
t = 8 cm
t priama = 20 cm
di tanya :
v?
jawab :
v = la × t prisma
v = ½ × a × t prisma
v = ½ × 6 × 8 × 20
v = 3 × 8 × 20
v = 450 cm²
2. v = luas × tinggi
v = 16 × 24 ×25
v = 348 × 25
v= 9.600 cm ^ 3
3. la = 240 cm²
v = 1/ 3 la × t
= 1/ 3 × 240 cm² × 30 cm
= 240 cm² × 10 cm
= 2400 cm²
4.luas alas
la = ½ × 6 × 8
= 6 × 4
= 24 cm²
volume = la × t
432. = 24 × t
432/24 = t
18. = t
= 18 cm
Penjelasan dengan langkah-langkah:
Soal No. 1
• Diketahui
Tinggi prisma = 20 cm
Alas segitiga = 6 cm
Tinggi segitiga = 8 cm
• Ditanyakan
Volume?
• Jawab
V = luas alas × t
= (½ × a × t) × t
= (½ × 6 × 8) × 20
= (3 × 8) × 20
= 24 × 20 =
Soal No 2.
• Diketahui
Panjang diagonal 1 = 16 cm
Panjang diagonal 2 = 24 cm
Tinggi prisma = 25 cm
• Ditanyakan
Volume?
• Jawab
V = luas alas × t
= (½ × × × t
= (½ × 16 × 24) × 25
= (8 × 24) × 25
= 192 × 25 =
Soal No. 3
• Diketahui
Luas alas = 240 cm²
Tinggi limas = 30 cm
• Ditanyakan
Volume?
• Jawab
V = ⅓ × luas alas × t
= ⅓ × 240 × 30
= 80 × 30 =
Soal No. 4
• Diketahui
Volume = 432 cm³
Alas segitiga = 6 cm
Tinggi segitiga = 8 cm
• Ditanyakan
Tinggi Prisma?
• Jawab
T =
=
=
=
=
Soal No. 5
=> Bagian A.
• Diketahui
Tinggi prisma = 20 cm
Alas segitiga = 30 cm
Tinggi segitiga = 40 cm
• Ditanyakan
Volume?
• Jawab
V = luas alas × tinggi
= (½ × a × t) × t
= (½ × 30 × 40) × 20
= (15 × 40) × 20
= 600 × 20 = 12.000 cm³
=> Bagian B.
• Diketahui
Panjang = 80 cm
Lebar = 40 cm
Tinggi = 50 cm
• Ditanyakan
Volume?
• Jawab
V = p × l × t
= 80 × 40 × 50
= 3.200 × 50 = 160.000 cm³
=> Bagian C.
• Diketahui
Tinggi Prisma = 18 dm
Alas segitiga = 6 dm
Tinggi segitiga = 8 dm
• Ditanyakan
Volume?
• Jawab
V = luas alas × t
= (½ × a × t) × t
= (½ × 6 × 8) × 18
= (3 × 8) × 18
= 24 × 18 = 432 dm³
Detail Jawaban:
Mapel: Matematika
Kelas: 8
Bab: Bab 8 Bangun Ruang
Kode kategorisasi: 8.2.8
Kata kunci: Volume, Bangun Ruang
#Semangat #RajinMencariIlmu