MhdFadil
4. luas alas = π r² 154 = 22/7 r² 1078 = 22 r² r² = 1078/22 r² = 49 r = √ 49 = 7 luas permukaan = 2 π r ( r + t ) = 2 x 22/7 x 7 ( 7 + 12 ) = 2 x 22 ( 19 ) = 836 cm² 5. keliling lingkaran = π d 44 = 22/7 d 308 = 22 d d = 308/22 d = 14 r = 14/2 = 7 luas permukaan = 2 π r ( r + t ) 880 = 2 x 22/7 x 7 ( 7 + t ) 880 = 44 ( 7 + t ) 880 = 308 + 44 t 44 t = 880 - 308 44 t = 572 t = 572 / 44 t = 13 cm
154 = 22/7 r²
1078 = 22 r²
r² = 1078/22
r² = 49
r = √ 49 = 7
luas permukaan = 2 π r ( r + t )
= 2 x 22/7 x 7 ( 7 + 12 )
= 2 x 22 ( 19 )
= 836 cm²
5. keliling lingkaran = π d
44 = 22/7 d
308 = 22 d
d = 308/22
d = 14
r = 14/2 = 7
luas permukaan = 2 π r ( r + t )
880 = 2 x 22/7 x 7 ( 7 + t )
880 = 44 ( 7 + t )
880 = 308 + 44 t
44 t = 880 - 308
44 t = 572
t = 572 / 44
t = 13 cm