Jawaban:
aljabar
1).
[tex]2 {x}^{2} - 4 = 0 \\ 2 {x}^{2} = 4 \\ {x}^{2} = \frac{4}{2} \\ {x}^{2} = 2 \\ x = \pm \sqrt{2} [/tex]
2).
[tex]6x + 8 - 2 = 2x + 4 \\ 6x + 6 = 2x + 4 \\ 6x - 2x = 4 - 6 \\ 4x = - 2 \\ x = - \frac{2}{4} \\ x = - \frac{1}{2} [/tex]
3).
[tex] - 8x + 2y + ( - 3) + 2x - 2y + 2 \\ - 8x + 2x + 2y - 2y - 3 + 2 \\ - 6x + 0 - 1 \\ - 6x - 1[/tex]
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Jawaban:
aljabar
1).
[tex]2 {x}^{2} - 4 = 0 \\ 2 {x}^{2} = 4 \\ {x}^{2} = \frac{4}{2} \\ {x}^{2} = 2 \\ x = \pm \sqrt{2} [/tex]
2).
[tex]6x + 8 - 2 = 2x + 4 \\ 6x + 6 = 2x + 4 \\ 6x - 2x = 4 - 6 \\ 4x = - 2 \\ x = - \frac{2}{4} \\ x = - \frac{1}{2} [/tex]
3).
[tex] - 8x + 2y + ( - 3) + 2x - 2y + 2 \\ - 8x + 2x + 2y - 2y - 3 + 2 \\ - 6x + 0 - 1 \\ - 6x - 1[/tex]