Jawaban:
det T = 2
det A = 32
B^-1 = [-4 1]
-11 3
Penjelasan dengan langkah-langkah:
dik T = [-2 4]
2 -5
det T |T|
= (ad-bc)
= (-2(-5)-4(2)
= (10-8)
= 2
dik matriks A = [2 -1 -4]
3 -2 0
-5 1 4
det A =
2 -1 -4 2 -1
3 -2 0 3 -2
-5 1 4 -5 1
= 2(-2)(4)+-1(0)(-5)+(-4)(3)(1)-(-4)(-2)(-5)-2(0)(1)-(-1)(3)(4)
= -8+0+(-12)-(-40)-0-(-12)
= -8+(-12)-(-40)-(-12)
= -8+(-12+40+12)
= -8+40
= 32
dik matriks B = [3 -1]
11 -4
invers B^-1=
B^-1 = 1/|B| adjoin B
=1/1 [-4 1]
=[-4 1]
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Jawaban:
det T = 2
det A = 32
B^-1 = [-4 1]
-11 3
Penjelasan dengan langkah-langkah:
dik T = [-2 4]
2 -5
det T |T|
= (ad-bc)
= (-2(-5)-4(2)
= (10-8)
= 2
dik matriks A = [2 -1 -4]
3 -2 0
-5 1 4
det A =
2 -1 -4 2 -1
3 -2 0 3 -2
-5 1 4 -5 1
= 2(-2)(4)+-1(0)(-5)+(-4)(3)(1)-(-4)(-2)(-5)-2(0)(1)-(-1)(3)(4)
= -8+0+(-12)-(-40)-0-(-12)
= -8+(-12)-(-40)-(-12)
= -8+(-12+40+12)
= -8+40
= 32
dik matriks B = [3 -1]
11 -4
invers B^-1=
B^-1 = 1/|B| adjoin B
=1/1 [-4 1]
-11 3
=[-4 1]
-11 3