No. 4 -------- Diket : Hambatan jenis tembaga, ρ = 1,7 x 10⁻⁸ ohm. meter luas penampang, A = 6,8 x 10⁻¹⁰ m² panjang kawat, L = 2 m
Tanya : Hambatan kawat, R = __?
Jawab : R = ρ.L/A R = 1,7 x 10⁻⁸ . 2 / 6,8 x 10⁻¹⁰ R = 50 ohm
No. 5 ------- Diket : Gambar rangkaian listrik R1 = 4 ohm R2 = 6 ohm R3 = 3 ohm
sumber ggl listrik baterai, ε = 12 V hambatan dalam, r = 0,6 ohm
Tanya : A. Hambatan pengganti, R = __? B. Kuat arus melewati R3 = 3 ohm, I3 = __? C. Kuat arus melewati R2 = 6 ohm, I2 = __? D. Tegangan jepit, V jepit = __?
Verified answer
No. 4--------
Diket :
Hambatan jenis tembaga, ρ = 1,7 x 10⁻⁸ ohm. meter
luas penampang, A = 6,8 x 10⁻¹⁰ m²
panjang kawat, L = 2 m
Tanya :
Hambatan kawat, R = __?
Jawab :
R = ρ.L/A
R = 1,7 x 10⁻⁸ . 2 / 6,8 x 10⁻¹⁰
R = 50 ohm
No. 5
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Diket :
Gambar rangkaian listrik
R1 = 4 ohm
R2 = 6 ohm
R3 = 3 ohm
sumber ggl listrik baterai, ε = 12 V
hambatan dalam, r = 0,6 ohm
Tanya :
A. Hambatan pengganti, R = __?
B. Kuat arus melewati R3 = 3 ohm, I3 = __?
C. Kuat arus melewati R2 = 6 ohm, I2 = __?
D. Tegangan jepit, V jepit = __?
Jawab :
A.
Step 1
--------
Hambatan R1 dan R2 disusun parelel, menjadi
1/R12 = 1/R1 + 1/R2
1/R12 = 1/4 + 1/6
1/R12 = 3/12 + 2/12 = 5/12
R12 = 12/5
R12 = 2,4 ohm
Step 2
---------
Kemudian gabungan R12 disusun Seri dengan R3, manjadi
R = R12 + R3
R = 2,4 + 3
R = 5,4 ohm
B. I3 = __?
Step 3
---------
Cari arus totalnya dulu yak, I = __?
I = ε / (R + r)
I = 12 / (5,4 + 0,6)
I = 12 / 6
I = 2 Ampere
Karena Hambatan R3 = 3 ohm disusun seri maka :
I3 = I = 2 Ampere
C. I2 = __?
I2 = [[R1 / (R1 + R2)] . I
I2 = [4 / (4 + 6)] . 2
I2 = [4 / (10)] . 2
I2 = 8/10
I2 = 0,8 A
D. V jepit = __?
V jepit = I.R
V jepit = 2 x 5,4
V jepit = 10,8 Volt
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