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p = 4x
l = 3x
t = x
Sehingga, diagonal ruang = √234 cm
Untuk itu:
√234 = √[p²+l²+t²]
Kuadratkan kedua ruas.
234 = p²+l²+t²
234 = (4x)²+(3x)³+(x)²
234 = 16x² + 9x² + x²
234 = 26x²
x² = 234/26
x² = 9
x = √9
Didapat, x = 3
Maka:
Panjang = 4x = 4(3) = 12 cm
Lebar = 3x = 3(3) = 9 cm
Tinggi = x = 3 cm
√234 = √ (4a)² + (3a)² + (a)²
√234 = √ 16a² + 9a² + a²
√234 = √ 26a²
234 = 26a²
a² = 234 / 26
a² = 9
a = √9
= 3
ukuran balok
panjang = 4 (a) = 4 (3) = 12 satuan
lebar = 3 (a) = 3 (3) = 9 satuan
tinggi = 1 (a) = 1 (3) =3 satuan