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²log 7= q -> log 7 = q log 2 ...(2)
substitusi log 2 (1) ke (2 )
log 7 = q log 2 = pq log 3
¹⁴ log 54 =log 54 /log 14= log 2.3³/log 2.7 = log 2+3log3 /log 2+log 7
= p log 3+3 log 3 / p log 3 +pq log 3
= log 3(p+3) / log 3 (p+pq) = (p+3)/ (p+pq) = (p+3 ) / p(1+q)
3. ( 2√3 - 1 / √7+4√3) × (√7 -4√3 / √7-4√3 ) = (2√21-8√9-√7+4√3) / 7-16.3
= 2√21-24-√7+4√3 /-41
2. 81(-2⁴) -32 = 81(32)-32 =2592 -32 = 2560