Jawab:
Penjelasan dengan langkah-langkah:
fungsi
soal 1
f(x) = 3 -2 x
2x = 3 - f(x)
x = 1/2 (3 - f(x)
f⁻¹ = ( 3 - x ) /2
soal2
f (x) = (2x + 1)²
2x + 1 = ± √ f(x)
2x = - 1 ± √ f(x)
x = 1/2 ( - 1 ± √ f(x))
soal 3
f(x) = x² + 4x - 7
x² + 4x = - 7 - f(x)
(x + 2)² = 4 - 7 - f(x)
(x + 2)² = - 3 - f(x)
x + 2 = ± √( - 3 - f(x))
x = - 2 ± √( - 3 - f(x))
soal 4
soal5
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Jawab:
Penjelasan dengan langkah-langkah:
fungsi
soal 1
f(x) = 3 -2 x
2x = 3 - f(x)
x = 1/2 (3 - f(x)
f⁻¹ = ( 3 - x ) /2
soal2
f (x) = (2x + 1)²
2x + 1 = ± √ f(x)
2x = - 1 ± √ f(x)
x = 1/2 ( - 1 ± √ f(x))
soal 3
f(x) = x² + 4x - 7
x² + 4x = - 7 - f(x)
(x + 2)² = 4 - 7 - f(x)
(x + 2)² = - 3 - f(x)
x + 2 = ± √( - 3 - f(x))
x = - 2 ± √( - 3 - f(x))
soal 4
soal5