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Answer 1

Verified answer

Integral trigonometri

∫ sin 3x dx , btas atas π, batas bawah π/2

= [- 1/3  cos 3x ](π...π/2)
= - 1/3 [ cos 3π - cos 3π/2 ]
= - 1/3 [-1 - 0]
= 1/3

Answer 2

Verified answer

INtegral TENtu

A = x⁴ /(x² - 1)
= x² + 1 + 1/(x² - 1)
= x² + 1 + 1/2 (1/(x - 1) - 1/(x + 1))

∫A dx [1...-1]
= x³/3 + x + 1/2 ln |(x - 1)/(x + 1)|

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