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y2 = 4x - 16
titk potong kedua nya y1 = y2
x^2 -6x = 4x- 16
x^2 - 10x + 16 = 0
(x-2)(x -8) = 0
x = 2 atau x = 8
V = π ₂⁸∫ y₂² - y₁² dx
V = π ₂⁸∫ [ (4x-16)² - (x²-6x)² ]dx
V = π ₂⁸∫ [ 16x² - 128x + 256 - x⁴ + 12x³ - 36x²]dx
V = π ₂⁸ ∫(-x⁴ +12x³ - 20x² - 128x + 256) dx
V = π [ - 1/5 x⁵ + 3x⁴ - 20/3 x³ - 64 x² + 256 x ]⁸₂
V = π [ -1/5(32.736) + 3(4.080)- 20/3(504) - 64(64-4) + 256(8-2) ]
V= π [- 6.547,2 + 12.240 - 3.360 - 3.840 +1.536
V = π (28,8) satuan