Tolong di bantu ya ini remidi gue besok -_- di ketahui kubus ABCD.EFGH dengan panjang rsuk 8 cm ditentukan jarak titik H ke diagonal ruang DF ?
whongaliemlihat Δ HDF siku" di H HF = 8√2 cm ( diagonal bidang) HD = 8 cm DF = 8√3 cm (diagonal ruang tarik garis HO tegak lurus DF HF² = OF x DF (8√2)² = OF x 8√3 128 = OF x 8√3 OF = = HD² = DO x DF 8² = DO x 8√3 64 = DO x 8√3 DO = = HO² = OF x DO = x = HO = = lihat sketsa di bawah .....
HF = 8√2 cm ( diagonal bidang)
HD = 8 cm
DF = 8√3 cm (diagonal ruang
tarik garis HO tegak lurus DF
HF² = OF x DF
(8√2)² = OF x 8√3
128 = OF x 8√3
OF =
=
HD² = DO x DF
8² = DO x 8√3
64 = DO x 8√3
DO =
=
HO² = OF x DO
= x
=
HO =
=
lihat sketsa di bawah .....
sehingga :
DH x HF= DF x DT --> DT : garis tinggi terhadap DF
DH : garis tinggi terhadap HF
DF : diagonal ruang = 8√3
HF = diogonal bidang = 8√2
8 x 8√2 = 8√3 x DT
DT = 8√2 / √3
= 8/3 √6