1. Diketahui:
Ditanyakan:
Jawab:
Maka,
(B)
2. Diketahui:
-5 < 4x + 3 < 7
x
-5 - 3 < 4x + 3 - 3 < 7 - 3
-8 < 4x < 4
-8/4 < 4x/4 < 4/4
-2 < x < 1
(E)
3. Diketahui:
|5x-15| = 10
|5x-15|² = 10²
25x²-150x+225 = 100
x²-6x+9 = 4
x²-6x+9-4 = 0
x²-6x+5 = 0
(x-5)(x-1) = 0
x = 5 atau x = 1 (E)
4. Diketahui:
|3x-7| = |2x+5|
|3x-7|² = |2x+5|²
9x²-42x+49 = 4x²+20x+25
9x²-42x+49-4x²-20x-25 = 0
5x²-62x+24 = 0
5x²-60x-2x+24 = 0
5x(x-12)-2(x-12) = 0
(5x-2)(x-12) = 0
x= 2/5 atau x=12
(D)
5. Diketahui:
f(x) = |3x-9|
f(2)
f(2) = |3(2)-9|
= |6-9|
= |-3|
= 3
6. Diketahui:
|x-2|+|2x+1| = 3
* |x-2| =
• x-2 jika x-2 ≥ 0 = x-2 jika x ≥ 2
• -(x-2) jika x-2 < 0 = -x+2 jika x < 2
* |2x+1| =
• 2x+1 jkka 2x+1 ≥ 0 = 2x+1 jika x ≥ -½
• -(2x+1) jika 2x+1 < 0 = -2x-1 jika x < -½
Gambar garis terlampir
1)Untuk x < -½
(-2x-1)+(-x+2) = 3
-3x+1 = 3
-3x = 2
x = -⅔ (✓)
2)Untuk -½≤ x <2
(-x+2)+(2x+1) = 3
x+3 = 3
x = 0 (✓)
3)Untuk x ≥ 2
(x-2)+(2x+1) = 3
3x-1 = 3
3x = 4
x = 4/3 (X)
HP = {0, -⅔}
(C)
7. Diketahui:
|3x+9| > 12
HP
|3x+9|² > 12²
9x²+54x+81 > 144
x²+6x+9 > 16
x²+6x+9-16 > 0
x²+6x-7 > 0
Cari Batas
x²+6x-7 = 0
(x+7)(x-1) = 0
x = -7 atau x = 1
HP = {x| x<-7 atau x>1}
Mapel: Matematika
Kelas: 10
Materi: Persamaan dan Pertidaksamaan Nilai Mutlak
1. B
2. E
3. E
4. D
5. E
Penjelasan dengan langkah-langkah:
1.
14x +35 = 9x- 30
14x - 9x = - 30 - 35
5x = - 65
x = -65/5
x = -13
nilai x + 8/2-x = (-13+8)/(2-(-13) = -5/15 = - 1/3
2.
-3-5 < 4x < 7 - 3
-8/4 < x < 4/4
-2<x< 1
3.
I5x-15I = 10
(i) 5x - 15 = 10
5x = 10 + 15
5x = 25
x = 5
(ii) 5x-15 = -10
5x = -10 + 15
5x = 5
x = 5/5
x = 1
4.
I3x-7I = I2x+5I
(3x-7)²=(2x+5)²
(i) (3x-7) = (2x+5)
3x -2x = 7 + 5
x = 12
(ii) 3x-7 = -(2x+5)
3x+2x = - 5 + 7
5x = 2
x = 2/5
5.
f(2) = I3.2-9I =I6-9I = I-3I = 3
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1. Diketahui:
Ditanyakan:
Jawab:
Maka,
(B)
2. Diketahui:
-5 < 4x + 3 < 7
Ditanyakan:
x
Jawab:
-5 < 4x + 3 < 7
-5 - 3 < 4x + 3 - 3 < 7 - 3
-8 < 4x < 4
-8/4 < 4x/4 < 4/4
-2 < x < 1
(E)
3. Diketahui:
|5x-15| = 10
Ditanyakan:
x
Jawab:
|5x-15| = 10
|5x-15|² = 10²
25x²-150x+225 = 100
x²-6x+9 = 4
x²-6x+9-4 = 0
x²-6x+5 = 0
(x-5)(x-1) = 0
x = 5 atau x = 1 (E)
4. Diketahui:
|3x-7| = |2x+5|
Ditanyakan:
x
Jawab:
|3x-7|² = |2x+5|²
9x²-42x+49 = 4x²+20x+25
9x²-42x+49-4x²-20x-25 = 0
5x²-62x+24 = 0
5x²-60x-2x+24 = 0
5x(x-12)-2(x-12) = 0
(5x-2)(x-12) = 0
x= 2/5 atau x=12
(D)
5. Diketahui:
f(x) = |3x-9|
Ditanyakan:
f(2)
Jawab:
f(2) = |3(2)-9|
= |6-9|
= |-3|
= 3
(E)
6. Diketahui:
|x-2|+|2x+1| = 3
Ditanyakan:
x
Jawab:
|x-2|+|2x+1| = 3
* |x-2| =
• x-2 jika x-2 ≥ 0 = x-2 jika x ≥ 2
• -(x-2) jika x-2 < 0 = -x+2 jika x < 2
* |2x+1| =
• 2x+1 jkka 2x+1 ≥ 0 = 2x+1 jika x ≥ -½
• -(2x+1) jika 2x+1 < 0 = -2x-1 jika x < -½
Gambar garis terlampir
1)Untuk x < -½
|x-2|+|2x+1| = 3
(-2x-1)+(-x+2) = 3
-3x+1 = 3
-3x = 2
x = -⅔ (✓)
2)Untuk -½≤ x <2
|x-2|+|2x+1| = 3
(-x+2)+(2x+1) = 3
x+3 = 3
x = 0 (✓)
3)Untuk x ≥ 2
|x-2|+|2x+1| = 3
(x-2)+(2x+1) = 3
3x-1 = 3
3x = 4
x = 4/3 (X)
HP = {0, -⅔}
(C)
7. Diketahui:
|3x+9| > 12
Ditanyakan:
HP
Jawab:
|3x+9| > 12
|3x+9|² > 12²
9x²+54x+81 > 144
x²+6x+9 > 16
x²+6x+9-16 > 0
x²+6x-7 > 0
Cari Batas
x²+6x-7 = 0
(x+7)(x-1) = 0
x = -7 atau x = 1
HP = {x| x<-7 atau x>1}
(B)
Mapel: Matematika
Kelas: 10
Materi: Persamaan dan Pertidaksamaan Nilai Mutlak
Jawab:
1. B
2. E
3. E
4. D
5. E
Penjelasan dengan langkah-langkah:
1.
14x +35 = 9x- 30
14x - 9x = - 30 - 35
5x = - 65
x = -65/5
x = -13
nilai x + 8/2-x = (-13+8)/(2-(-13) = -5/15 = - 1/3
2.
-5 < 4x + 3 < 7
-3-5 < 4x < 7 - 3
-8 < 4x < 4
-8/4 < x < 4/4
-2<x< 1
3.
I5x-15I = 10
(i) 5x - 15 = 10
5x = 10 + 15
5x = 25
x = 5
(ii) 5x-15 = -10
5x = -10 + 15
5x = 5
x = 5/5
x = 1
4.
I3x-7I = I2x+5I
(3x-7)²=(2x+5)²
(i) (3x-7) = (2x+5)
3x -2x = 7 + 5
x = 12
(ii) 3x-7 = -(2x+5)
3x+2x = - 5 + 7
5x = 2
x = 2/5
5.
f(2) = I3.2-9I =I6-9I = I-3I = 3