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A B C
A = 2p
B = 10
C = 9
r diketahui = 5
maka pusat P (A, B) --> P(- (2p) , (10) )
jadi pusat P (-p,-5)
r² = (-1/2A)²+(-1/2B)²-C
25 = p²+5²-9
25 = p²+25-9
p² = 9
p = 3
sehingga pusat lingkaran P (3,-5)
5. x²+y²-4x+8y-p=0
P (2,-4)
pers garis singgung : 3x-4y = 0,
3x = 4y
y = 3/4 x
m₁ =
gradien m₁ tegak lurus dengan gradien m₂ jari'2 lingkaran
sehingga m₂ = -
pers garis jari2 : y+4 = - (x-2)
--------------------------------------- x 3
3y+12 = -4x+8
3y+4x = -4
titik potong garis singgung dan garis jari2
3x-4y = 0 Ix4 --> 12x-16y=0
4x+3y = -4 Ix3 --> 12x+9y =-12
------------------- -
-25y = 12
y = -
3x-4(- ) = 0
3x = -
x = -
titik potong (- , - )
sehingga r² = (x₁-a)² + (y₁-b)²
= (-2)²+(+4)²
= (
= +
=
r =
r =
r² = (-1/2A)²+(-1/2B)² - C
= 2² + (-4)² + p
= 20+p
p = - 20
= 19,36 - 20
= - 0,64
≈ 0
silahkan di re-check prosesnya sebelum menjadi jawaban akhir
semoga membantu