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R.awal = 100 Ω
γ = 4 x 10^-3 /°C
R.akhir 212 Ω
ΔR = γ x ΔT
212 - 100 = 4 x 10^-3 x (T.akhir - T.awal)
112 = 4 x 10^-3 x (T.akhir - 25)
112 / (4 x 10^-3) = T.akhir - 25
280 = T.akhir - 25
T.akhir = 280 + 25 = 305 °C