Jawaban:
[tex]6. \: luas \: permukaan \: kerucut = \\ (\pi{ {r}^{2} }) + (\pi{rs}) \\ s = \sqrt{ {r}^{2} + {t}^{2} } \\ s = \sqrt{ {7}^{2} + {24}^{2} } \\ s = \sqrt{ 49 + 576 } \\ s = \sqrt{625 \\ } \\ s = 25 \: cm \\ ( \frac{22}{7} \times {7}^{2} ) + ( \frac{22}{7} \times 7 \times 25) \\ = 154 + 550 \\ = 704 \: {cm}^{2} \: (salah)[/tex]
[tex]10. \: luas \: permukaan \: kubus = \\ 6 \times s \times s \\ 6 \times 10 \times 10 \\ = 600 \: {cm}^{2} \\ luas \: permukaan \: balok = \\ 2 \times (pl + pt + lt) \\ 2 \times (20 \times 10 + 20 \times 10 + 10 \times 10) \\ = 2 \times (200 + 200 + 100) \\ = 2 \times 500 \\ = 1.000 \: {cm}^{2} \\ luas \: sisi \: tertutup = \\ 2 \times (10 \times 10) \\ = 2 \times 100 \\ = 200 \: {cm}^{2} \\ luas \: permukaan = \\ 600 + 1.000 - 200 \\ = 1.400 \: {cm}^{2} \: (benar)[/tex]
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Jawaban:
[tex]6. \: luas \: permukaan \: kerucut = \\ (\pi{ {r}^{2} }) + (\pi{rs}) \\ s = \sqrt{ {r}^{2} + {t}^{2} } \\ s = \sqrt{ {7}^{2} + {24}^{2} } \\ s = \sqrt{ 49 + 576 } \\ s = \sqrt{625 \\ } \\ s = 25 \: cm \\ ( \frac{22}{7} \times {7}^{2} ) + ( \frac{22}{7} \times 7 \times 25) \\ = 154 + 550 \\ = 704 \: {cm}^{2} \: (salah)[/tex]
[tex]10. \: luas \: permukaan \: kubus = \\ 6 \times s \times s \\ 6 \times 10 \times 10 \\ = 600 \: {cm}^{2} \\ luas \: permukaan \: balok = \\ 2 \times (pl + pt + lt) \\ 2 \times (20 \times 10 + 20 \times 10 + 10 \times 10) \\ = 2 \times (200 + 200 + 100) \\ = 2 \times 500 \\ = 1.000 \: {cm}^{2} \\ luas \: sisi \: tertutup = \\ 2 \times (10 \times 10) \\ = 2 \times 100 \\ = 200 \: {cm}^{2} \\ luas \: permukaan = \\ 600 + 1.000 - 200 \\ = 1.400 \: {cm}^{2} \: (benar)[/tex]