Diketahui :
[tex]q₁ = 5 \times {10}^{ - 6} C \\ q₂ = 4 \times {10}^{ - 6} C \\ r = 3cm = 3 \times {10}^{ - 2} m[/tex]
Ditanya : Fc = ...?
Jawaban :
[tex]Fc = k \times \frac{q₁ \times q₂}{ {r}^{2} } \\ Fc = 9 \times {10}^{9} Nm²/C² \times \frac{5 \times {10}^{ - 6} C \times 4 \times {10}^{ - 6}C}{ {(3 \times {10}^{ - 2}m)}^{2} } \\ Fc = 9 \times {10}^{9} Nm²/C²\times \frac{20 \times {10}^{ - 12}C²}{9 \times {10}^{ - 4} {m}^{2} } \\ Fc = 20 \times 10N \\ Fc = 2 \times {10}^{2} N[/tex]
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Jangan Lupa Jadikan Jawaban Terbaik yaa :D
Wanwan selalu membantumu :^
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Diketahui :
[tex]q₁ = 5 \times {10}^{ - 6} C \\ q₂ = 4 \times {10}^{ - 6} C \\ r = 3cm = 3 \times {10}^{ - 2} m[/tex]
Ditanya : Fc = ...?
Jawaban :
[tex]Fc = k \times \frac{q₁ \times q₂}{ {r}^{2} } \\ Fc = 9 \times {10}^{9} Nm²/C² \times \frac{5 \times {10}^{ - 6} C \times 4 \times {10}^{ - 6}C}{ {(3 \times {10}^{ - 2}m)}^{2} } \\ Fc = 9 \times {10}^{9} Nm²/C²\times \frac{20 \times {10}^{ - 12}C²}{9 \times {10}^{ - 4} {m}^{2} } \\ Fc = 20 \times 10N \\ Fc = 2 \times {10}^{2} N[/tex]
Semoga membantu :D
Jangan Lupa Jadikan Jawaban Terbaik yaa :D
Wanwan selalu membantumu :^
#MATEMATIKAMENYENANGKAN