a. f(x) = 4x² - 12x + 9
( - b/2a, - d/4a)
x = - (12)/2 (4) = 12/8
= 3/2
d = b²n - 4ac
- (12 )² - 4 (4 ) ( 9)
= 144 - 144 = 0
y = - d/4a
= - 0 / 4/(4)
= 0
koordinat titik balik fungsi (x,y) = ( 3/2,0) ✔
b. xp = - b/2a
= - ( - 12) /2( 4 )
= 12/8
Jadi sumbu simetrinya adalah x 3/2✔
c. Nilai minimum :
- d/4a = - b² - 4ac/4a
= - ( - 12)² - 4( 4 ) ( 9 )/ 4/( 4 )
= - 144 - 144/ 16
= - 0/16
= 0 ✔
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a. f(x) = 4x² - 12x + 9
( - b/2a, - d/4a)
x = - (12)/2 (4) = 12/8
= 3/2
d = b²n - 4ac
- (12 )² - 4 (4 ) ( 9)
= 144 - 144 = 0
y = - d/4a
= - 0 / 4/(4)
= 0
koordinat titik balik fungsi (x,y) = ( 3/2,0) ✔
b. xp = - b/2a
= - ( - 12) /2( 4 )
= 12/8
= 3/2
Jadi sumbu simetrinya adalah x 3/2✔
c. Nilai minimum :
- d/4a = - b² - 4ac/4a
= - ( - 12)² - 4( 4 ) ( 9 )/ 4/( 4 )
= - 144 - 144/ 16
= - 0/16
= 0 ✔
Penjelasan + cara ada digambar
Semoga membantu