Jawab:
(i) Perimeter = AB + BC + CD + AD
11,5x - 14 = (3x - 4) + 2(x - 1) + CD + 1,5x
11,5x - 14 = 3x - 4 + 2x - 2 + CD + 1,5x
11,5x - 14 = 6,5x - 6 + CD
CD = 11,5x - 6,5x - 14 + 6
CD = 5x - 8
(ii) AD = BC
1,5x = 2(x - 1)
1,5x = 2x - 2
2x - 1,5x = 2
0,5x = 2
x = 2 : 0,5 = 4
AB = 3x - 4 = 3(4) - 4 = 12 - 4 = 8 cm
BC = 2(x - 1) = 2x - 2 = 2(4) - 2 = 8 - 2 = 6 cm
CD = 5x 8 = 5(4) - 8 = 20 - 8 = 12 cm
AD = 1,5x = 1,5(4) = 6 cm
Perimeter = AB + BC + CD + AD
8 + 6 + 12 + 6 = 32 cm
(iii) Area of the trapezium =
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Jawab:
(i) Perimeter = AB + BC + CD + AD
11,5x - 14 = (3x - 4) + 2(x - 1) + CD + 1,5x
11,5x - 14 = 3x - 4 + 2x - 2 + CD + 1,5x
11,5x - 14 = 6,5x - 6 + CD
CD = 11,5x - 6,5x - 14 + 6
CD = 5x - 8
(ii) AD = BC
1,5x = 2(x - 1)
1,5x = 2x - 2
2x - 1,5x = 2
0,5x = 2
x = 2 : 0,5 = 4
AB = 3x - 4 = 3(4) - 4 = 12 - 4 = 8 cm
BC = 2(x - 1) = 2x - 2 = 2(4) - 2 = 8 - 2 = 6 cm
CD = 5x 8 = 5(4) - 8 = 20 - 8 = 12 cm
AD = 1,5x = 1,5(4) = 6 cm
Perimeter = AB + BC + CD + AD
8 + 6 + 12 + 6 = 32 cm
(iii) Area of the trapezium =