Penjelasan dengan langkah-langkah:
Diketahui :
m = 20 kg
F = 178 N
a = 2√2 m/s²
Φ = 45°
Ditanya :
N = ?
Uk = ?
Jawab :
ΣFy = 0
F . sin Φ + N - w = 0
178 . sin45 + N = m . g
178 . 1/2√2 + N = 20 . 10
89√2 + N = 200
N = 200 - 89√2
ΣFx = m . a
F . cos Φ - fk = m . a
F . cos Φ - Uk . N = m . a
178 . cos45 - Uk . 200 - 89√2 = 20 . 2√2
178 . 1/2√2 - (200 - 89√2)Uk = 40√2
89√2 - (200 - 89√2)Uk = 40√2
(89√2 - 40√2)/(200 - 89√2) = Uk
- 40√2/200 = Uk
-0,28 = Uk
Jadi , Koefisien geseknya adalah -0,28 N
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Penjelasan dengan langkah-langkah:
Diketahui :
m = 20 kg
F = 178 N
a = 2√2 m/s²
Φ = 45°
Ditanya :
N = ?
Uk = ?
Jawab :
ΣFy = 0
F . sin Φ + N - w = 0
178 . sin45 + N = m . g
178 . 1/2√2 + N = 20 . 10
89√2 + N = 200
N = 200 - 89√2
ΣFx = m . a
F . cos Φ - fk = m . a
F . cos Φ - Uk . N = m . a
178 . cos45 - Uk . 200 - 89√2 = 20 . 2√2
178 . 1/2√2 - (200 - 89√2)Uk = 40√2
89√2 - (200 - 89√2)Uk = 40√2
(89√2 - 40√2)/(200 - 89√2) = Uk
- 40√2/200 = Uk
-0,28 = Uk
Jadi , Koefisien geseknya adalah -0,28 N