" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Pembilang pada suku pertama:
3^1 + 3^0 + 3^(-1) = 3 + 1 + 1/3 = 4 1/3 = 13/3
Penyebut pada suku pertama:
3^(-3) + 3^(-2) + 3^(-1)
= 1/(3^3)+1/(3^2)+1/(3^1)
= 1/27 + 1/9 + 1/3
= 1/27 + 3/27 + 9/27
= (1+3+9)/27
= 13/27
Suku kedua:
[3^1 + 3^(-1) ]^(-1)
= [(3 + 1/3)]^(-1)
= (10/3)^(-1)
= 10^(-1) / 3^(-1)
= 3^1/10^1
= 3/10
Soal di atas sudah disederhanakan
menjadi
(13/3 : 13/27) + 3/10
Kemudian kita selesaikan,yaitu
(13/3 : 13/27) + 3/10
= (13/3 × 27/13) + 3/10
= (27/3) + 3/10
= 9 + 3/10
= 9 + 0,3
= 9,3
Jawab
b. 9,3
Catatan
tanda ^ dibaca pangkat
Selamat belajar
@Wello1☺